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                albus就是要第一个出场                </h1>
                <p>时间限制：6s&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;  空间限制：128MB</p>			</div>
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                                <h3>题目描述</h3><p><div>已知一个长度为n的正整数序列A（下标从1开始）， 令 S = { x | 1 &lt;= x &lt;= n }, S 的幂集2^S定义为S 所有子</div>
<div>集构成的集合。定义映射 f : 2^S -&gt; Zf(空集) = 0f(T) = XOR A[t] , 对于一切t属于T现在albus把2^S中每个集</div>
<div>合的f值计算出来， 从小到大排成一行， 记为序列B（下标从1开始）。 给定一个数， 那么这个数在序列B中第1</div>
<div>次出现时的下标是多少呢？</div></p><hr/><h3>输入格式</h3><p><p>第一行一个数n, 为序列A的长度。接下来一行n个数， 为序列A， 用空格隔开。最后一个数Q， 为给定的数.</p></p><hr/><h3>输出格式</h3><p><div>共一行， 一个整数， 为Q在序列B中第一次出现时的下标模10086的值.</div>
<div></div></p><hr/><h3>样例输入</h3><pre>3
1 2 3
1</pre><hr/><h3>样例输出</h3><pre>3
样例解释：
N = 3, A = [1 2 3]
S = {1, 2, 3}
2^S = {空, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}
f(空) = 0
f({1}) = 1
f({2}) = 2
f({3}) = 3
f({1, 2}) = 1 xor 2 = 3
f({1, 3}) = 1 xor 3 = 2
f({2, 3}) = 2 xor 3 = 1
f({1, 2, 3}) = 0
所以
B = [0, 0, 1, 1, 2, 2, 3, 3]
</pre><hr/><h3>提示</h3><p><p>数据范围：<br />
1 &lt;= N &lt;= 10,0000<br />
其他所有输入均不超过10^9</p>
<p></p></p><hr/><h3>题目来源</h3><p>湖北省队互测

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